3x^2-320x-6000=0

Solution for 3x^2-320x-6000=0 equation:

3x^2-320x-6000=0

a = 3; b = -320; c = -6000;
Δ = b2-4ac
Δ = -3202-4·3·(-6000)
Δ = 174400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{174400}=\sqrt{1600*109}=\sqrt{1600}*\sqrt{109}=40\sqrt{109}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-320)-40\sqrt{109}}{2*3}=\frac{320-40\sqrt{109}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-320)+40\sqrt{109}}{2*3}=\frac{320+40\sqrt{109}}{6}
$